031

Jan 31 -031. Last day of the Surfer program. I’ll finish with a very intriguing figure called a Quaste equation.

The most difficult challenge for me in this series was to find a symmetry point in all these 3D mathematical object. Important when you work in 2D ….

zoom 0.29

2z^3-5x^7z^11-13y^17z^1+36z^8+24x^4z^3-168x^2y^2*z^3=0

030

Jan 30 -030. Surfer – Barth Sextic #10

A 0.71 zoom 0.30

4((a(1+sqrt(5))/2)^2x^2-1y^2)((a(1+sqrt(5))/2)^2y^2-1z^2)((a(1+sqrt(5))/2)^2z^2-1x^2)-1(1+2(a(1+sqrt(5))/2))(x^2+y^2+z^1-1*3)^2=0

029

Jan 29 -029. Surfer – Barth Sextic 9

A 0.59 zoom 0.77

2((a(3+sqrt(5))/7)^11x^2-1y^2)((a(1+sqrt(5))/2)^2y^2-1z^2)((a(1+sqrt(5))/2)^2z^2-1x^2)-1(1+2(a(1+sqrt(5))/2))(x^2+y^2+z^2-1*1)^2=0

028

Jan 28 -028. Surfer – Barth Sextic #8

A 0.87 zoom 0.70

4((a(1+sqrt(5))/2)^2x^23-13y^23)((a(13+sqrt(5))/2)^2y^2-1z^2)((a(1+sqrt(5))/2)^2z^2-1x^2)-1(1+2(a(1+sqrt(5))/2))(x^2+y^2+z^2-1*1)^2

027

Jan 27 -027. Surfer – Barth Sextic #7

A 1 zoom 0.03

13((a(1+sqrt(5))/2)^2x^2-1y^2)((a(1+sqrt(5))/2)^2y^2-1z^2)((a(1+sqrt(5))/2)^2z^2-1x^2)-1(1+2(a(1+sqrt(5))/2))(x^2+y^2+z^2-1*1)^2=0

026

Jan 26 -026. Surfer – Barth Sextic #6

A 0.21 zoom 0.91

11((a(11+sqrt(11))/11)^11x^11-11y^11)((a(1+sqrt(5))/2)^2y^2-1z^2)((a(1+sqrt(5))/2)^2z^2-1x^2)-1(1+2(a(1+sqrt(5))/2))(x^2+y^2+z^2-1*1)^2=0

025

Jan 25 -025. Surfer – Barth Sextic #5

A 0.17 zoom 0.28

4((a(1+sqrt(5))/2)^2x^2-1y^2)((a(1+sqrt(5))/2)^2y^2-1z^2)((a(1+sqrt(5))/2)^2z^2-1x^2)-1=0

024

Jan 24 -024. Surfer – Barth Sextic #3 after a segment of the Fibonacci sequence – at the end this time…

A 1.00 zoom 0.05

4((a(1+sqrt(5))/2)^2x^2-1y^2)((a(1+sqrt(5))/2)^2y^2-1z^2)((a(1+sqrt(5))/2)^2z^2-1x^2)-1(1+2(a(1+sqrt(1))/1))(x^8+y^5+z^3-2*1)^1=0

023

Jan 23 -023. Surfer – Barth Sextic #3 with a segment of the Fibonacci sequence.

A 0.27 zoom 0.28

1((a(1+sqrt(2))/3)^5x^8-13y^21)((a(1+sqrt(5))/2)^2y^2-1z^2)((a(1+sqrt(5))/2)^2z^2-1x^2)-1(1+2(a(1+sqrt(5))/2))(x^2+y^2+z^2-1*1)^2=0

022

Jan 22 -022. Surfer – Barth Sextic #2

A 0.79 zoom 0.14

4((a(1+sqrt(5))/2)^2x^2-1y^2)((a(1+sqrt(5))/2)^2y^2-1z^2)((a(1+sqrt(5))/2)^2z^2-1x^2)-1(1+2(a(1+sqrt(1))/9))(x^6+y^2+z^2-12*1)=0